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View Full Version : Ok, How The Hell Does This Work???



MagicMtnDan
06-08-2006, 10:19 PM
I'm sure there's a good explanation for it but I am mesmerized by it (try it!) (http://www.learnenglish.org.uk/games/magic-gopher-central.swf)

speed zero
06-08-2006, 10:30 PM
wtf i tried it 4 time in a row got it every time im scared i think im going to sit in a corner and cry

Magic34
06-08-2006, 10:39 PM
I got it. There are only certain digits that will work each time and the symbols change each time as well. So all the digits it will work with will have the same symbol, but because there are so many #'s and symbols it throws you off.
Watch, try 2 #'s at a time by doing the math and compare the 2 different numbers you come up with on the chart with the symbols. They will be the same symbol.

Magic34
06-08-2006, 10:40 PM
Look at #'s like 9 and 36, always the same symbol and they both work for the equation on different #'s you pick.
That will be $2.00 please. :crossx:

MagicMtnDan
06-08-2006, 11:06 PM
I got it. There are only certain digits that will work each time and the symbols change each time as well. So all the digits it will work with will have the same symbol, but because there are so many #'s and symbols it throws you off.
Watch, try 2 #'s at a time by doing the math and compare the 2 different numbers you come up with on the chart with the symbols. They will be the same symbol.
So, why is it right EVERY time?

Thorsinc
06-08-2006, 11:16 PM
I see dead people

Kilrtoy
06-08-2006, 11:33 PM
that was cool

Magic34
06-09-2006, 12:03 AM
So, why is it right EVERY time?
Because doing the equation as they instruct will have limited results each time with the same numbers.
Take 43, 10, 81, and 17.
4 totally different random numbers.
So the #'s you get at the end using the ones above have a symbol, so go to the symbol part and look at the symbols next to the following #'s that we get from the ones above.
36, 9, 72, 9 (you can see repitition with 10 and 17 yielding the same results already)
36, 9, 72 will all have the same symbols.
They change the symbols each time you try it again to really throw it off.
Now you owe me $4.
Let's look at a bunch of random #'s here. The # we pick will be first and the solution # will be in ()
43(36), 10(9), 81(72), 45(36), 22(18), 36 (27), 99 (81), 77(63).
So doing this, there is another pattern. Every number with a multiple of 9 is the end result #. So the following #'s whould have the exact same sybbols every single time on the chart. Compare these numbers on the chart.
9, 18, 27, 36, 45, 54, 63, 72, 81 <-- These are the only possible results each time.
OK, now I want $9.

YeLLowBoaT
06-09-2006, 01:00 AM
ok lets see if I can explain it a generally.... Take any 2 digit #( it does not matter which one.) now if you add those the two digits toegther and subtract them form then origanal # you will end up with a number that has 9 as a factor. so all you have to do is make the symbole for every multable of 9 the same.
Some guy in the 1600's came up with a therom....If you want me to look up they guy that came up with it, that will be $100 or a tank of gas in my truck... whichs ever is cheaper... :crossx:

CHEETAH24
06-09-2006, 06:36 AM
I got it !!...the gopher is the devil.